Index:
[thread]
[date]
[subject]
[author]
From: Brian Appel <bra2@acpub.duke.edu>
To :
Date: Wed, 31 Mar 1999 01:46:27 -0500
Re: rounds per game to win
--------------361A136CA659CE563388B90E
Content-Type: text/plain; charset=us-ascii
Content-Transfer-Encoding: 7bit
One strategy is to not care about the other players ... i.e. the dice are the
true enemy
An easy way to get around 10 is to roll 5 times every turn. This is because
every roll is not dependent on the previous roll, you always have a 1 in 6
chance on a die so I assume that I can roll five times to get all the legal
numbers ie I roll a 2,3,4,5,6 on each die and avoid the 1. I modified simple
simon to roll 1,2,3,4,5,6,7 ... times and 5 gave the best average. No matter how
many die you roll you always have a 1 in 6 chance of getting a 1 but for
snakeeyes there is a 1/36 chance (in the grand scheme of probabilty there are
three ways to lose 1 - die1, 1 - die2, or both 1s so you have a 7/36 chance to
lose) ... the thing is that about 5 times out of 6 the average dictates that you
get a good number
FlashFlood wrote:
> I was forgetting to update my rolls each time. Now I am getting about 15
> rounds per game. Nine sounds a little low. I checked a lot of combinations
> of strategies and nothing was under 15 rounds per game.
>
> -Donnie
--------------361A136CA659CE563388B90E
Content-Type: text/html; charset=us-ascii
Content-Transfer-Encoding: 7bit
<!doctype html public "-//w3c//dtd html 4.0 transitional//en">
<html>
One strategy is to not care about the other players ... i.e. the dice are
the true enemy
<p>An easy way to get around 10 is to roll 5 times every turn. This
is because every roll is not dependent on the previous roll, you always
have a 1 in 6 chance on a die so I assume that I can roll five times to
get all the legal numbers ie I roll a 2,3,4,5,6 on each die and avoid the
1. I modified simple simon to roll 1,2,3,4,5,6,7 ... times and 5
gave the best average. No matter how many die you roll you always have
a 1 in 6 chance of getting a 1 but for snakeeyes there is a 1/36 chance
(in the grand scheme of probabilty there are three ways to lose 1 - die1,
1 - die2, or both 1s so you have a 7/36 chance to lose) ... the thing is
that <i>about</i> <i>5</i> times out of 6 the average dictates that you
get a good number
<p>FlashFlood wrote:
<blockquote TYPE=CITE>I was forgetting to update my rolls each time.
Now I am getting about 15
<br>rounds per game. Nine sounds a little low. I checked a
lot of combinations
<br>of strategies and nothing was under 15 rounds per game.
<p>-Donnie</blockquote>
</html>
--------------361A136CA659CE563388B90E--
Index:
[thread]
[date]
[subject]
[author]