Hardness Results

  TSP metric TSP
ratio of 1 NP-hard NP-hard
ratio of 2 NP-hard polynomial

Proved the hardness results for exact metric TSP already (since $2
\le 1 + 1$).

The hardness for a ratio of 2 come from replacing the distance 2 edges with distance 2 n edges (violating the ``metric'' property). Then, if there is a Hamiltonian circuit, the approximation algorithm would have to give us a tour of length no more than 2 n. Such a tour could only consist of the length 1 edges and, therefore, would indicate the existence of a Hamiltonian circuit in the original graph.


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