recieve

iei = 3

eii = -1

---------------

values = [1, 2, 3]
         [0, 2, 3]
         [0, 2 , 3]
         [ 0, 2, 4]         



previous = 1
           2
           4

idx = 1     note:  1, 2
      2


def double(x):
    return 2 * x


double(x)
y = double(x)
print double(x)

[5] + [7, 8]
[5, 7, 8]

[5] + [[7,8]]
[5, [7,8]]

[5] + 7

NO


x = x + 4
x += 4


return side

2 (x + 4)
2 * ( x + 4)