CompSci 101 Exam 1 Sec 01 and Sec 02 Fall 2014 Solutions
Note Problems 1 and 5 are different for the two sections.

SEC 01 PROBLEM 1. A. output:
5.1
17
<type 'int'>
2
2

SEC 01  PROBLEM 1. B. output:
e
Novr
-1
dog
['parrot', 'fox']

SEC 02 PROBLEM 1. A. output:
4.1
15
<type 'float'>
1
1

SEC 02  PROBLEM 1. B. output:
g
gustt
2
parrot
['dog', 'parrot', 'fox']


PROBLEM 2 A. 

def equationsEqual(x):
    equation1 = 2 *((x + 1)**2) - 1
    equation2 = (2*x + 1) **2
    return equation1 == equation2

ALTERNATIVE SOLN:

def equationsEqual(x):
    equation1 = 2 *((x + 1)*(x+1)) - 1
    equation2 = (2*x + 1)* (2*x + 1)
    return equation1 == equation2

ALTERNATIVE SOLN:

def equationsEqual(x):
    equation1 = 2 *((x + 1)**2) - 1
    equation2 = (2*x + 1) **2
    if equation1 == equation2:
        return True
    else:
        return False

ALTERNATIVE SOLN:

def equationsEqual(x):
    return (2 *((x + 1)**2) - 1) == (2*x + 1) **2


PROBLEM 2. B.

def convertPrice(price, day, month):
    if not(month == 'January' or month == "July"):
        price = price + price * .10
    if day=="Monday":
        price -= 5.0
    if price < 1.0:
        price = 1.0
    return price

ALTERNATIVE SOLUTION

def convertPrice2(price, day, month):
    if (month == 'January' or month == "July"):
        price = price    # you have to have at least one statement in the body
    else:
        price = price + price * .10
    if day=="Monday":
        price -= 5.0
    if price < 1.0:
        price = 1.0
    return price

ALTERNATIVE SOLUTION
    
def convertPrice3(price, day, month):
    if (month == 'January' or month == "July") :
        if day == "Monday":
            if price <= 6:
                return 1.0
            else: 
                return price - 5
        else: 
            return price
    else: 
        if day == "Monday":
            if price + price * .10 <= 6:
                return 1.0
            else: 
                return price + price * .10 - 5.0
        else: 
            return price * 1.10


PROBLEM 3. A. 

Q1. 
doHaveCarWithColor(carColors,'blue')  returns False and should return True

Q2. 
The function returns after executing the for loop just once. The If
statement returns a value whether it the condition is True or False.

Q3. 
To correct it, remove the else case. Here is the correct Code:

def doHaveCarWithColor(clist, color):
    for carColor in clist:
        if carColor == color:
            return True
    return False


PROBLEM 3 B.

B1.
['Sarah', 'Aaron', 'Salman']

B2.
['Sarah', 'Salman']

B3.
Sarah

B4.
Mystery returns the name of length greater than 4 that starts with S. If
there are multiple such names, it returns the first one. 

B5.
["Sue", "Beth"]

After executing the first for loop the list x is empty, the second for loop
does not execute since there are no items in the list. The program crashes
on y[0] as there are no items in the list. 

PROBLEM 4.

def stretchOut(word):
    word = word.lower()
    if word[0] in "aeiou" or len(word) <= 2:
        return word
    return word[0] + word[0] + word[1] + word[1] + word[2:] + "eh"

ALTERNATIVE SOLUTION:
    
def stretchOut(word):
    word = word.lower()
    if word[0] in "aeiou":
        return word
    if len(word) <=2:
        return word
    return word[0] + word[0] + word[1] + word[1] + word[2:] + "eh"

ALTERNATIVE SOLUTION:

def stretchOut(word):
    word = word.lower()
    if IsVowel(word[0]):
        return word
    if len(word) <=2:
        return word
    newWord = word[0] * 2 + word[1] * 2
    newWord += word[2:] + "eh"
    return newWord

ALTERNATIVE SOLUTION:
    
def stretchOut(word):
    word = word.lower()
    if len(word) < 3 or IsVowel(word[0]):
        return word 
    newWord = ""
    for index in range(len(word)):
        if index < 2:
            newWord += word[index] + word[index]
        else:
            newWord += word[index]
    newWord += "eh"        
    return newWord  
            
SEC 01 PROBLEM 5A.

def listOfSectNums(alist, year): 
    secList = [ ]
    for line in alist:   
        items = line.split(":")
        if items[-1] == year:
            secList += [items[2] ]
    return secList

ALTERNATIVE SOLUTION WITH append

def listOfSectNums(alist, year): 
    secList = [ ]
    for line in alist:   
        items = line.split(":")
        if items[-1] == year:
            secList.append(items[2])
    return secList
        
SEC 01 PROBLEM 5B.
        
def numberOf(data, sect, year): 
    somelist = listOfSectNums(data, year)
    count = 0
    for item in somelist:   
        if item == sect:
            count += 1
    return count

ALTERNATIVE SOLUTION:

def numberOf(data, sect, year): 
    somelist = listOfSectNums(data, year)
    sectList = []
    for item in somelist:   
        if item == sect:
            sectList += [item]
    return len(sectList)

ALTERNATIVE SOLUTION:

def numberOf(data, sect, year):
    return listOfSectNums(data, year).count(sect)

SEC 02 PROBLEM 5A.

def listOfYears(data, sect): 
    yearList = [ ]
    for line in data:   
        items = line.split(":")
        if items[2] == sect:
            yearList += [items[-1] ]
    return yearList
        
ALTERNATIVE SOLUTION with APPEND:

def listOfYears(data, sect): 
    yearList = [ ]
    for line in data:   
        items = line.split(":")
        if items[2] == sect:
            yearList.append(items[-1])
    return yearList
        

SEC 02 PROBLEM 5B.

def numberOf(data, sect, year): 
    somelist = listOfYears(data, sect)
    count = 0
    for item in somelist:   
        if item == year:
            count += 1
    return count

ALTERNATIVE SOLUTION:

def numberOf(data, sect, year): 
    somelist = listOfYears(data, sect)
    yearList = []
    for item in somelist:   
        if item == year:
            yearList += [item]
    return len(yearList)

ALTERNATIVE SOLUTION:

def numberOf(data, sect, year): 
    return listOfYears(data, sect).count(year)